python解决一元二次方程问题

#二次方程的处理

import math

achar=input("请输入一元二次方程的三个系数:")
bchar=input()
cchar=input()
#print(a,b,c)

a=int(achar)
b=int(bchar)
c=int(cchar)

discriminant=b*b-4*a*c
if discriminant==0:
    print("the equation have one key!")
    c=math.sqrt(discriminant)
    x=-b/(a*2)
    print("x1 = x2 =",x)
elif discriminant>0:
    print("the equation have two real keys!")
    c=math.sqrt(discriminant)
    x1=(-b+c)/(a*2)
    x2=(-b-c)/(a*2)
    print("x1 =",x1,"x2 =",x2)
else :
    print("the equation have two imaginary keys!")
    c=complex(0,1)*math.sqrt(-discriminant)
    x1=(-b+c)/(a*2)
    x2=(-b-c)/(a*2)
    print("x1 =",x1,"x2 =",x2)

程序的中complex（0，1），结果其实就是1j再乘判别式的相反数开根号

作者：学海无涯w